How do you solve for h in #a= ch + f #?

1 Answer
Jun 22, 2016

We work to isolate the variable we want by doing the same operation to both sides of our equation arriving at

#c=(a-f)/h#

Explanation:

We work to isolate the variable we want by doing the same operation to both sides of our equation. In this case, we can also start by writing the equation in a different order, writing the right-hand-side first, which doesn't change the equality:

#ch+f=a#

Now we can subtract #f# from both sides:

#ch +f -f = a -f#

which simplifies to

#ch = a-f#

Now we can divide both sides by #h#

#(ch)/h = (a-f)/h#

Which simplifies to

#c=(a-f)/h#