Question

How do you solve for k in `3k+6t=b+5`?

Answer 1

`k=1/3(b+5-6t)`

Explanation:

Isolate the k term on the left side and place all other terms on the right.

hence : 3k = b + 5 - 6t

Now divide both sides by 3 to obtain k.

`rArr(cancel(3) k)/cancel(3)=(b+5-6t)/3 =1/3(b+5-6t)`