How do you solve for n in $2n - 4m = 8$ ?

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Answer 1 · 2018-03-10T17:15:09

See a solution process below:

First, add $color(red)(4m)$ to each side of the equation to isolate the $n$ term while keeping the equation balanced:

$2n - 4m + color(red)(4m) = 8 + color(red)(4m)$

$2n - 0 = 8 + 4m$

$2n = 8 + 4m$

Now, divide by $color(red)(2)$ to solve for $n$ while keeping the equation balanced:

$(2n)/color(red)(2) = (8 + 4m)/color(red)(2)$

$(color(red)(cancel(color(black)(2)))n)/cancel(color(red)(2)) = 8/color(red)(2) + (4m)/color(red)(2)$

$n = 4 + 2m$

Answer 2 · 2018-03-10T17:18:25

$n=2(m+2)$

Add $4m$ to both sides

$2n=8+4m$

Divide both sides by $2$

$n=4+2m$

Take a factor of $2$ out of $4m+2$

$n=2(2+m)$

How do you solve for n in 2n - 4m = 82n - 4m = 8?