Question

How do you solve for p in `3p - 2q = 37`?

Answer 1

`p=1/3(37+2q)`

Explanation:

`"isolate "3p" by adding "2q" to both sides"`

`3pcancel(-2q)cancel(+2q)=37+2q`

`3p=37+2q`

`"divide both sides by 3"`

`(cancel(3) p)/cancel(3)=(37+2q)/3`

`p=(37+2q)/3=1/3(37+2q)`