How do you solve for s in $D = C - s / n$ ?

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Answer 1 · 2015-08-03T09:21:30

$s=(C-D)*n$

First we have to move expression with $s$ to left side, and expressions without $s$ to the right side:

After first move we get:

$s/n+D=C$ - moved $(-s/n)$ left

$s/n=C-D$ - moved $D$ right

Last step is multiplying both sides by $n$

$s=(C-D)*n$

How do you solve for s in D = C - s / nD = C - s / n?