How do you solve for x: $3 | 2 x - 1 | - 4 = 29$ $3|2x − 1| − 4 = 29$ ?

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Answer 1 · 2017-08-02T10:14:54

Solution : $x = 6 or x = - 5$ $x=6 or x = -5$

1) $3 | 2 x - 1 | - 4 = 29 or 3 | 2 x - 1 | = 29 + 4 or | 2 x - 1 | = \frac{33}{3}$ $3|2x-1|-4 = 29 or 3|2x-1| = 29+4 or |2x-1| = 33/3$ or

$| 2 x - 1 | = 11 or 2 x - 1 = 11 or 2 x = 12 or x = 6$ $|2x-1| = 11 or 2x -1 = 11 or 2x = 12 or x=6$ OR

2) $3 | 2 x - 1 | - 4 = 29 or 3 | 2 x - 1 | = 29 + 4 or | 2 x - 1 | = \frac{33}{3}$ $3|2x-1|-4 = 29 or 3|2x-1| = 29+4 or |2x-1| = 33/3$ or

$| 2 x - 1 | = 11 or 2 x - 1 = - 11 or 2 x = - 10 or x = - 5$ $|2x-1| = 11 or 2x -1 = -11 or 2x = -10 or x= -5$

Solution : $x = 6 or x = - 5$ $x=6 or x = -5$ [Ans]

Answer 2 · 2018-08-04T01:14:51

$x = 6$ $x=6$ and $x = - 5$ $x=-5$

Let's start by adding $4$ $4$ to both sides to get

$3 | 2 x - 1 | = 33$ $3|2x-1|=33$

Next, we can divide both sides by $3$ $3$ to get

$| 2 x - 1 | = 11$ $|2x-1|=11$

We have two different scenarios:

$2 x - 1 = 11$ $2x-1=11$ and $2 x - 1 = - 11$ $2x-1=-11$

For both, we can add $1$ $1$ to both sides to get

$2 x = 12$ $2x=12$ and $2 x = - 10$ $2x=-10$

Dividing both sides by $2$ $2$ , we get

$x = 6$ $x=6$ and $x = - 5$ $x=-5$

Hope this helps!

How do you solve for x: 3|2x − 1| − 4 = 293|2x−1|−4=293|2x − 1| − 4 = 29?