Question

How do you solve for x for `ln1 - lne = x`?

Answer 1

The result should be: `x=-1`

Consider that from the definition of logarithm:

`log_ab=x =>a^x=b`

and that `log_e` is `ln`;

So you get:

`ln1=0` because `e^0=1`

`lne=1` because `e^1=e`

in your equation.:

`0-1=x`

`x=-1`