How do you solve for x in $2x + 3y = 6$ ?

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Answer 1 · 2018-05-24T12:02:58

See a solution process below:

First, subtract $color(red)(3y)$ from each side of the equation to isolate the $x$ term while keeping the equation balanced:

$2x + 3y - color(red)(3y) = 6 - color(red)(3y)$

$2x + 0 = 6 - 3y$

$2x = 6 - 3y$

Now, divide each side of the equation by $color(red)(2)$ to solve for $x$ while keeping the equation balanced:

$(2x)/color(red)(2) = (6 - 3y)/color(red)(2)$

$(color(red)(cancel(color(black)(2)))x)/cancel(color(red)(2)) = (6 - 3y)/2$

$x = (6 - 3y)/2$

Or

$x = 6/2 - (3y)/2$

$x = 3 - 3/2y$

How do you solve for x in 2x + 3y = 62x + 3y = 6?