How do you solve for x in $(5a)/x = (5b)/(x-1)$ ?

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Answer 1 · 2016-02-26T15:33:50

First, simplify by the property $a/b = m/n -> a xx n = b xx m$

$5bx = (x - 1)5a$

$5bx = 5ax - 5a$

$5bx - 5ax = -5a$

$5x(b - a) = -5a$

$5x = (-5a)/(b - a)$

$x = -((5a)/(b - a)) / 5$

$x = - (5a) / (5(b - a))$

$x = - (5a)/(5b - 5a)$

Practice exercises:

a) $(1 + 5a)/(2x)= (3z - 4x)/(5a)$

b). $1/(2x) + 1/(yz) = 3/(xzy)$

Good luck!

How do you solve for x in (5a)/x = (5b)/(x-1)(5a)/x = (5b)/(x-1)?