How do you solve for x in $5ax-c=4c+ax$ ?

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Answer 1 · 2016-03-17T18:31:07

$x=(5c)/(4a$

$1$ . Group all like terms together. Start by subtracting $ax$ from both sides of the equation.

$5ax-c=4c+ax$

$5ax$ $color(red)(-ax)-c=4c+ax$ $color(red)(-ax)$

$4ax-c=4c$

$2$ . Continue grouping all like terms together by adding $c$ to both sides.

$4ax-c$ $color(blue)(+c)=4c$ $color(blue)(+c)$

$4ax=5c$

$3$ . Isolate for $x$ by dividing both sides by $4a$ .

$(4ax)/color(darkorange)(4a)=(5c)/color(darkorange)(4a)$

$color(green)(|bar(ul(color(white)(a/a)x=(5c)/(4a)color(white)(a/a)|)))$

How do you solve for x in 5ax-c=4c+ax 5ax-c=4c+ax ?