How do you solve for x in $a^2x+b^2x+7=3c$ ?

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Answer 1 · 2016-11-08T01:10:00

Isolate all terms with $x$ on one side of the equation.

$a^2x + b^2x = 3c - 7$

$x(a^2 + b^2) = 3c - 7$

$x = (3c - 7)/(a^2 + b^2)$

Hopefully this helps!

How do you solve for x in a^2x+b^2x+7=3ca^2x+b^2x+7=3c?