Question

How do you solve for x in `a(x + c ) = b( x - c )`?

Answer 1

It is

`a(x + c ) = b( x - c )`
`a*x + a*c = b* x -b* c`
`a*x-b*x=-a*c-b*c`
`x*(a-b)=-c*(a+b)`

Now if `a-b!=0` then `x=-c*(a+b)/(a-b)`