Question

How do you solve for x in `ax-k=bx+h`?

Answer 1

`color(green)(x) = (h + k)/(a - b )`

Explanation:

`color(green)(ax) - k = color(green)(bx) + h`

`color(green)(ax - bx ) = h + k`

`color(green)(x)(a - b ) = h + k`

`color(green)(x) = (h + k)/(a - b )`