How do you solve for x in $n= (x+y-1)/(xy)$ ?

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Answer 1 · 2016-03-09T14:07:04

$x= (y-1)/(n y -1)$

$n = (x+y-1)/color(blue)((xy)$

$n * color(blue)(xy)= (x+y-1)$

$n xy= x+y-1$

Isolating terms containing $x$ towards the L.H.S:

$n xy - x= y-1$

$x(n y -1)= y-1$

$x= (y-1)/(n y -1)$

How do you solve for x in n= (x+y-1)/(xy)n= (x+y-1)/(xy)?