How do you solve for x in $p(x-1)+7=r(x-4)$ ?

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Answer 1 · 2016-02-22T19:21:11

$x = (-4r - 7 +p)/ (p -r)$

$p (x-1) +7 = r (x-4)$

$p (x ) + p xx (-1) +7 = r (x) + r xx (-4)$

$px -p +7 = rx -4r$

$px - rx = -4r - 7 +p$

$x (p -r) = -4r - 7 +p$

$x = (-4r - 7 +p)/ (p -r)$

How do you solve for x in p(x-1)+7=r(x-4)p(x-1)+7=r(x-4)?