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How do you solve for x in $x/(3-j) = (j/2)$ ?

1 Answer

Mar 13, 2016

$x= (3j - j^2)/2$

Explanation:

$x/ (3-j)= j/2$

Isolating $x$ on the L.H.S:

$x= (j/2) * (3-j)$

$x= (3j - j^2)/2$

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