How do you solve for x in #x/4+6=13#?

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Answer 1 · 2016-04-13T17:09:52

#x=28#

In order to solve for x in the equation #x/4 + 6 = 13#

begin by isolating the term with #x# by subtracting #6# from both sides of the equation

#x/4 cancel(+ 6) cancel(-6) = 13 -6#

#x/4=7#

now multiply by #4# on each side to isolate the #x# variable

#x/cancel4 cancel(4)=7(4)#

#x=28#