How do you solve for y in $2x + 3y = 3$ ?

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Answer 1 · 2018-03-27T00:08:46

$y=-2/3x+1$

Move the $x$ term to the right side, then divide everything by $3$ :

$2x+3y=3$

$3y+2x=3$

$3y+2xcolor(blue)-color(blue)(2x)=3color(blue)-color(blue)(2x)$

$3ycolor(red)cancelcolor(black)(color(black)+2xcolor(blue)-color(blue)(2x))=3color(blue)-color(blue)(2x)$

$3y=3color(blue)-color(blue)(2x)$

$3y=-2x+3$

$color(blue)(color(black)(3y)/3)=color(blue)(color(black)(-2x+3)/3)$

$color(blue)(color(black)(color(red)cancelcolor(black)3y)/color(red)cancelcolor(blue)3)=color(blue)(color(black)(-2x+3)/3)$

$y=color(blue)(color(black)(-2x+3)/3)$

$y=color(blue)(color(black)(-2x)/3)+color(blue)(color(black)3/3)$

$y=color(blue)(color(black)(-2x)/3)+1$

$y=-2/3x+1$

That is solving for $y$ . Hope this helped!

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