How do you solve for y in $3 x + 4 y = 12$ $3x +4y=12$ ?

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Answer 1 · 2016-03-06T15:00:57

$y = \frac{12 - 3 x}{4}$ $y=color(blue)((12-3x)/4$

$3 x + 4 y = 12$ $3x+color(green)(4y)=12$

To solve for $y$ $y$ we would need to isolate the term containing $y$ $y$ on the L.H.S

$4 y = 12 - 3 x$ $4y=12-color(green)(3x$

$y = \frac{12 - 3 x}{4}$ $y=color(blue)((12-3x)/4$

How do you solve for y in 3x+4y=123x +4y=12?