How do you solve for y in $- 3 x y + 4 y = 10$ $-3xy + 4y = 10$ ?

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Answer 1 · 2016-03-22T19:02:51

Factor $y$ $y$ out of the expression on the left side
then divided both sides by the other factor
to get $y = \frac{10}{4 - 3 x}$ $y=10/(4-3x)$

$- 3 x y + 4 y = 10$ $-3xy+4y=10$

$y (- 3 x + 4) = 10$ $y(-3x+4)=10$

$y = \frac{10}{4 - 3 x}$ $y=10/(4-3x)$

How do you solve for y in -3xy + 4y = 10−3xy+4y=10-3xy + 4y = 10?