How do you solve for y in $5y - q = 20$ ?

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Answer 1 · 2016-03-28T06:34:27

$y=(q+20)/5$

We start from the given equation

$5y-q=20$

Transpose $q$ to the right of the equation

$5y=20+q$

Divide both sides by 5

$(5y)/5=(20+q)/5$

$(cancel5y)/cancel5=(20+q)/5$

$y=(q+20)/5$

God bless....I hope the explanation is useful.

How do you solve for y in 5y - q = 205y - q = 20?