How do you solve for y in #6x-3y=9#?

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Answer 1 · 2016-11-11T04:34:02

#y=2x-3#

As we have two variables #x# and #y# here

so we can solve for #y# only in terms of #x#.

As #6x-3y=9#, adding #3y-9# to both sides, we get

#6x-3y+3y-9=9+3y-9#

or #6x-cancel(3y)+cancel(3y)-9=cancel9+3y-cancel9#

or #6x-9=3y#

or #3y=6x-9# - now multipying both sides by #1/3#, we get

#1/3xx3y=1/3xx6x-1/3xx9#

or #y=2x-3#