How do you solve for y in $x=(y+2)/(5y-1)$ ?

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Answer 1 · 2016-06-19T09:10:11

$color(blue)(y = (2 + x) / (5x - 1)$

$x = (color(blue)(y)+2) / (5color(blue)(y) -1)$

Our main motive in solving this question should be to isolate $color(blue)(y:$

$x * (5color(blue)(y) -1) = color(blue)(y)+2$

We multiply $x$ with both terms within the bracket.

$x * (5color(blue)(y)) + x *( -1) = color(blue)(y)+2$

$5xcolor(blue)(y) -x = color(blue)(y)+2$

$5xcolor(blue)(y) - color(blue)(y) = 2 + x$

$color(blue)(y)(5x - 1) = 2 + x$

$color(blue)(y = (2 + x) / (5x - 1)$

How do you solve for y in x=(y+2)/(5y-1)x=(y+2)/(5y-1)?