How do you solve for z in $4 z = 2 z + b d$ $4z=2z+bd$ ?

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Answer 1 · 2016-03-06T19:00:19

$z = \frac{b d}{2}$ $z=(bd)/2$

Subtract $2 z$ $2z$ from both sides of the equation.

$4 z - 2 z = 2 z + b d - 2 z$ $4z-2z=2z+bd-2z$

$2 z = b d$ $2z=bd$

Divide both sides by $2$ $2$ .

$z = \frac{b d}{2}$ $z=(bd)/2$

How do you solve for z in 4z=2z+bd4z=2z+bd?