How do you solve for z in $a/3-z = b/3+z$ ?

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Answer 1 · 2016-03-29T16:55:52

$color(blue)(z) = (a- b)/(6)$

$a/ 3 - color(blue)(z) = b/3 + color(blue)(z$

$a/ 3 - b/3 = color(blue)(z +z$

$(a- b)/3 = color(blue)(2z$

$color(blue)(z) = (a- b)/(3 * 2)$

$color(blue)(z) = (a- b)/(6)$

How do you solve for z in a/3-z = b/3+za/3-z = b/3+z?