How do you solve for zz in xz+y=1+zxz+y=1+z?

1 Answer
Mar 17, 2018

See a solution process below:

Explanation:

First, subtract color(red)(y)y and color(blue)(z)z from each side of the equation to isolate the zz terms while keeping the equation balanced:

xz - color(blue)(z) + y - color(red)(y) = 1 - color(red)(y) + z - color(blue)(z)xzz+yy=1y+zz

xz - z + 0 = 1 - y + 0xzz+0=1y+0

xz - z = 1 - yxzz=1y

Next, factor a zz out of each term on the left giving:

z(x - 1) = 1 - yz(x1)=1y

Now, divide each side of the equation by color(red)(x - 1)x1 to solve for zz while keeping the equation balanced:

(z(x - 1))/color(red)(x - 1) = (1 - y)/color(red)(x - 1)z(x1)x1=1yx1

(zcolor(red)(cancel(color(black)((x - 1)))))/cancel(color(red)(x - 1)) = (1 - y)/(x - 1)

z = (1 - y)/(x - 1)