How do you solve for z in y^2 - 4x = 8z - 3yzy2−4x=8z−3yz?

2 Answers
Max G.
May 10, 2017

Not possible

Explanation:

For each variable you want to solve for, a separate equation is needed. For example, if you want to solve for xx in x=5*2x=5⋅2, you only need one equation. If you wanted xx and yy, you would need a system of two equations. If you wanted three variables, you need three equations, so on and so forth.

Y
May 10, 2017

Use distributive property on the right-hand side and isolate zz.

Explanation:

First we can use the distributive property to take out the zz on the right-hand side:
y^2-4x=z(8-3y)y2−4x=z(8−3y)

To isolate the zz, we can divide over the 8-3y8−3y:
z=(y^2-4x)/(8-3y)z=y2−4x8−3y, where y!=8/3y≠83 which gives us the expression for z

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