How do you solve $\frac{3}{2y} = \frac{16}{y + 2}$ ?

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Answer 1 · 2016-09-21T16:47:09

$y=6/29$

Turn the whole thing upside down

$(2y)/3=(y+2)/16$

Cross multiply

$16(2y)=3(y+2)$

$32y=3y+6$

Subtract $3y$ from both sides

$29y=6$

Divide both sides by 29

$y=6/29$

How do you solve \frac{3}{2y} = \frac{16}{y + 2}\frac{3}{2y} = \frac{16}{y + 2}?