How do you solve $\frac { 4z } { 7} - 8= 1$ ?

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Answer 1 · 2018-07-27T04:41:02

$z = 15.75$

$(4z)/7 - 8 = 1$

Add $color(blue)8$ to both sides:
$(4z)/7 - 8 quadcolor(blue)(+quad8) = 1 quadcolor(blue)(+quad8)$

$(4z)/7 = 9$

Multiply both sides by $color(blue)(7)$ :
$(4z)/7 color(blue)(*7) = 9 color(blue)(*7)$

$4z = 63$

Divide both sides by $color(blue)4$ :
$(4z)/color(blue)4 = 63/color(blue)4$

$z = 15.75$

Hope this helps!

How do you solve \frac { 4z } { 7} - 8= 1\frac { 4z } { 7} - 8= 1?