How do you solve $\frac { 5} { 8} + \frac { 3} { 2} ( 4- \frac { 1} { 4} ) - \frac { 1} { 8}$ ?

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Answer 1 · 2018-03-11T12:15:21

$21/4$

$5/8+3/2((4*4-1)/4)-1/8$

$5/8+3/2((16-1)/4)-1/8$

$5/8+3/2(15/4) -1/8$

$5/8+45/8-1/8$

$(5+45-8)/8$

$(50-8)/8$

$42/8$

$21/4" "$ (divide the numerator and the denominator by $2$ )

How do you solve \frac { 5} { 8} + \frac { 3} { 2} ( 4- \frac { 1} { 4} ) - \frac { 1} { 8}\frac { 5} { 8} + \frac { 3} { 2} ( 4- \frac { 1} { 4} ) - \frac { 1} { 8}?