How do you solve $h = -16t^2 + 3200$ ?

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Answer 1 · 2017-07-24T10:12:48

Solve for $h=0$ ? $h=$ maximum?

$h=0$ :
$0=-16t^2+3200->$
$16t^2=3200->t^2=3200/16=200->$
$t_(1,2)=+-sqrt200=+-10sqrt2$

$h=$ maximum:
$->t=0->h=3200$

How do you solve h = -16t^2 + 3200h = -16t^2 + 3200?