How do you solve $k+(-6)=2$ ?

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Answer 1 · 2016-11-28T01:43:44

$k = 8$

To solve this problem first eliminate the parenthesis:

$k + (-6) = 2$

$k - 6 = 2$

Now we can add 6 to each side to isolate and solve for $k$ while keeping the equation balanced:

$k - 6 + 6 = 2 + 6$

$k - 0 = 8$

$k = 8$

How do you solve k+(-6)=2k+(-6)=2?