How do you solve $ln (1 - 8 n) - 10 = - 7$ $ln(1-8n)-10=-7$ ?

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Answer 1 · 2018-06-13T14:08:01

$n = \frac{1 - e^{3}}{8} \approx - 2.386$ $n=(1-e^3)/8~~-2.386$

$ln (1 - 8 n) - 10 = - 7$ $ln(1-8n)-10=-7$

$ln (1 - 8 n) = 3$ $ln(1-8n)=3$

$1 - 8 n = e^{3}$ $1-8n=e^3$

$8 n = 1 - e^{3}$ $8n=1-e^3$

$n = \frac{1 - e^{3}}{8} \approx - 2.386$ $n=(1-e^3)/8~~-2.386$

Answer 2 · 2018-06-13T14:09:37

$n = \frac{1 - e^{3}}{8}$ $n = \frac{1-e^3}{8}$

Add $10$ $10$ to both sides:

$ln (1 - 8 n) = 3$ $ln(1-8n) = 3$

Consider both sides as exponents of $e$ $e$ :

$e^{ln (1 - 8 n)} = e^{3}$ $e^{ln(1-8n)} = e^3$

$\therefore 1-8n = e^3$

Subtract $1$ from both sides

$-8n = e^3-1$

Divide both sides by $-8$ :

$n = \frac{1-e^3}{8}$

How do you solve ln(1-8n)-10=-7ln(1−8n)−10=−7ln(1-8n)-10=-7?