How do you solve $ln e^x -ln e^3 = ln e^9$ ?

Question

2001 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-07-07T20:28:09

If you use the properties of logarithms, you will need to refer to these:

OR

$lne^z = z$

where $a$ and $b$ are constants, $e = 2.718281828cdots$ , and $z$ is either a constant or a variable. Therefore, we can do this:

$lne^x - lne^3 = lne^9$

$lne^x = lne^9 + lne^3$

$xcancel(lne) = 9cancel(lne) + 3cancel(lne)$

$color(blue)(x) = 9 + 3 = color(blue)(12)$

How do you solve ln e^x -ln e^3 = ln e^9ln e^x -ln e^3 = ln e^9?