How do you solve $ln (x - 3) = 1$ $ln (x-3)= 1$ ?

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Answer 1 · 2016-05-31T03:45:55

$x = 3 + e = 4.718$ $x=3+e=4.718$ , nearly.

Inversely, $x - 3 = e^{1} = e = 2.718$ $x-3 = e^1=e=2.718$ , nearly.

So, $x = 3 + e = 4.718$ $x = 3+e=4.718$ , nearly

How do you solve ln(x−3)=1ln (x-3)= 1?