How do you solve $ln x - ln (\frac{1}{x}) = 2$ $ln x - ln (1/x) = 2$ ?

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Answer 1 · 2018-04-27T12:38:04

$x = e$ $x=e$

As $ln x - ln (\frac{1}{x}) = 2$ $lnx-ln(1/x)=2$

we have $ln (\frac{x}{\frac{1}{x}}) = 2$ $ln(x/(1/x))=2$

or ${ln x}^{2} = 2$ $lnx^2=2$

or $2 ln x = 2$ $2lnx=2$

or $ln x = 1$ $lnx=1$

and $x = e$ $x=e$

How do you solve lnx−ln(1x)=2ln x - ln (1/x) = 2?