Question

How do you solve `ln2x=4`?

Answer 1

`x=(e^4)/2~=27.3`

Explanation:

Start with the original:

`ln(2x)=4`

We can take both sides and put them as exponents of `e`. On the left side, this is taking one function (`ln`) and applying the inverse to it (`e`), so the result is that they cancel out and we end up with the term inside the `ln`:

`2x=e^4`

`x=(e^4)/2~=27.3`