How do you solve $ln3+ln(2x^2+4)=ln12$ ?

Question

2574 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-08-10T16:57:25

x=0

Since $lna+lnb=ln(ab)$ , then

$ln3+ln(2x^2+4)=ln12$

is equivalent to:

$ln(3(2x^2+4))=ln12$ .

that's equivalent to:

$3(2x^2+4)=12$

$6x^2+12=12$

$6x^2=0$

$x=0$

How do you solve ln3+ln(2x^2+4)=ln12ln3+ln(2x^2+4)=ln12?