How do you solve $ln8-ln(x+4)=1$ ?

Question

4154 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-08-21T17:40:59

$x=8/e-4=-1.057$

$ln8-ln(x+4)=1$ can be written as

$ln8-ln(x+4)=lne$ or

$ln8/(x+4)=lne$ or

$8/(x+4)=e$ or

$x+4=8/e$

i.e. $x=8/e-4$ or

$x=2.943-4=-1.057$

How do you solve ln8-ln(x+4)=1ln8-ln(x+4)=1?