How do you solve ${log}_{2} x = 5$ $log_2x=5$ ?

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Answer 1 · 2016-11-16T01:49:12

Recognize that the notation means “the log base number raised to the power is… that will help you to set up the solution to a problem in any base.

Recognize that the notation means “the log base number raised to the power is… that will help you to set up the solution to a problem in any base.

${log}_{b a s e}$ $log_(base)$ x = exponent on the base number.

In this case, it is “The number that results from raising 2 (the base) to the 5th power.
$2^{5} = x$ $2^5 = x$
x = 32

ANOTHER example would be:
${log}_{4} x = 3$ $log_4x = 3$ In this case, the base is 4 and the exponent is 3.
$4^{3} = x$ $4^3 = x$
x = 64

How do you solve log2x=5log_2x=5?