How do you solve ${log}_{3} x = 2$ $log_3 x=2$ ?

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Answer 1 · 2016-10-09T06:51:41

$x = 9$ $x=9$

We can write log problems two different ways:

${log}_{a} b = c$ $log_(a)b=c$

$a^{c} = b$ $a^c=b$

So we can take the original question:

${log}_{3} x = 2$ $log_3x=2$

and rewrite it to:

$3^{2} = x = 9$ $3^2=x=9$

How do you solve log_3 x=2log3x=2log_3 x=2?