How do you solve ${log}_{3} y = 5$ $log_3 y =5$ ?

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Answer 1 · 2016-08-14T17:37:23

$y = 243$ $y=243$

${log}_{a} b = x; \to b = a^{x}$ $log_a b=x" ; " rarr b=a^x$

${log}_{3} y = 5$ $log_3 y=5$

$y = 3^{5}$ $y=3^5$

$y = 243$ $y=243$

How do you solve log_3 y =5log3y=5log_3 y =5?