How do you solve $log_5(5^(6n+1))=13$ ?

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Answer 1 · 2016-10-24T02:27:56

$n = 2$

$log_5 5^(6n + 1) = 13$

$log_n m^x = x log_n m$

$=> (6n + 1)log_5 5 = 13$

$log_n n = 1$

$=> 6n + 1 = 13$

$=> 6n = 12$

$=> n = 2$

How do you solve log_5(5^(6n+1))=13log_5(5^(6n+1))=13?