How do you solve $log_6(2x-3)=log_6(x+2)$ ?

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Answer 1 · 2016-12-04T18:39:27

The logarithms can be canceled, because $log(a) = log(b)$ means that $a = b$
Answer: $x = 5$

The logarithms can be canceled, because $log(a) = log(b)$ means that $a = b$ :

$2x - 3 = x + 2$

$x = 5$

How do you solve log_6(2x-3)=log_6(x+2)log_6(2x-3)=log_6(x+2)?