How do you solve $m^2 - 2m - 3 = 0$ graphically?

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Answer 1 · 2018-06-01T06:52:12

Either create a table of values and plot them or see below

The y intercept is (0,3)

$(-b)/(2a)=2/2=1$ this is the x coordinate of the vertex. When x=1, y=-4
(1,-4) is the vertex

$m^2-2m-3=0 => (m-3)(m+1)=0$

m=3 or m=-1 these are the x intercepts

The graph is a $uu$ shaped parabola, with a line of symmetry at x=1, a minimum at (1,-4), y intercept at -3 and x intercepts at -1 & 3

How do you solve m^2 - 2m - 3 = 0 m^2 - 2m - 3 = 0 graphically?