How do you solve #m/4<2# or #-3+m>7#?

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Answer 1 · 2018-07-27T19:16:24

See a solution process below:

Solve each inequality for #m#:

Inequality 1:

#m/4 < 2#

#color(red)(4) xx m/4 < color(red)(4) xx 2#

#cancel(color(red)(4)) xx m/color(red)(cancel(color(black)(4))) < 8#

#m < 8#

Inequality 2:

#-3 + m > 7#

#-3 + color(red)(3) + m > 7 + color(red)(3)#

#0 + m > 10#

#m > 10#

The Solution Is:

#m < 8#; #m > 10#

Or, in interval notation:

#(-oo, 8)#; #(10, +oo)#

Answer 2 · 2018-07-27T22:35:41

#m<8# or #m>10#

For the first inequality

#m/4<2#, let's multiply both sides by #4# to get

#m<8#

For our second inequality, we can add #3# to both sides to get

#m>10#

Therefore, the solution to these inequalities is

#m<8# or #m>10#

Hope this helps!