How do you solve $N - \frac{1}{5} = \frac{7}{20}$ $N-1/5=7/20$ ?

Question

3367 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-12-05T16:20:11

$N = \frac{11}{20}$ $N = 11/20$

First, isolate the $N$ $N$ term on one side of the equation and the fractions on the other side of the equation while keeping the equation balanced:

$N - \frac{1}{5} + \frac{1}{5} = \frac{7}{20} + \frac{1}{5}$ $N - 1/5 + 1/5 = 7/20 + 1/5$

$N - 0 = \frac{7}{20} + \frac{1}{5}$ $N - 0 = 7/20 + 1/5$

$N = \frac{7}{20} + \frac{1}{5}$ $N = 7/20 + 1/5$

Next we need to get the constants over a common denominator, in this case 20, by multiplying by the correct form of $1$ $1$ :

$N = \frac{7}{20} + (\frac{1}{5} \cdot \frac{4}{4})$ $N = 7/20 + (1/5 * 4/4)$

$N = \frac{7}{20} + \frac{4}{20}$ $N = 7/20 + 4/20$

$N = \frac{11}{20}$ $N = 11/20$

How do you solve N−15=720N-1/5=7/20?