How do you solve $n^2 + 3n - 12 = 6$ ?

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Answer 1 · 2018-04-29T04:42:09

$n=-6,3$

Given: $n^2+3n-12=6$ .

Subtract $6$ from both sides.

$n^2+3n-12-6=color(red)cancelcolor(black)6-color(red)cancelcolor(black)6$

$n^2+3n-18=0$

$=>(n+6)(n-3)=0$

$:.n=-6,3$

How do you solve n^2 + 3n - 12 = 6 n^2 + 3n - 12 = 6?