How do you solve $n^2 + 7n + 15 = 5$ by factoring?

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Answer 1 · 2018-05-14T19:30:56

$n=-2 and n=-5$

Given: $n^2+7n+15=5$

Subtract 5 from both sides

$n^2+7n+10=0$

Note that $2xx5=10 and 2+5=7$ giving:

$(n+2)(n+5)=0$

Thus: $n=-2 and n=-5$

How do you solve n^2 + 7n + 15 = 5n^2 + 7n + 15 = 5 by factoring?