How do you solve p2+4p=−1?

1 Answer
Veddesh ϕ
Apr 12, 2016

x=−2±√3

Explanation:

p2+4p=−1

Add 1 both sides

→p2+4p+1=−1+1

→p2+4p+1=0

This is a Quadratic equation (in form ax2+bx+c=0)

Use the Quadratic formula

x=−b±√b2−4ac2a

Remember that aandb are the coefficients of p2andp and c is the constant number

So,

(a,b,c)=(1,4,1)

→x=−4±√42−4(1)(1)2(1)

→x=−4±√16−42

→x=−4±√122

→x=−4±√4⋅32

→x=−4±2√32

Cancel

→x=−42±21√321

x=−2±√3

Remember that the symbol ± means plus or minus

So,

It implies that,

x=−2+√3,−2−√3

If you need more guidance for the Quadratic formula

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